D(X-Y)+[E(X-Y)]^2=DX+DY-2(EXY-EXEY)+(EX-EY)^2怎么推导出来的?

x=(e^t)sint y=(e^t)cost 求d^2y/dx^2 e^y+xy=e 求 d^2y/dx^2｜x=0 求详解 设x=e^(-t) 试变换方程x^2 d^2y/dx^2 +xdy/dx+y=0 设函数y=y(x)由x=1-e^t和y=t+e^-t确定,求dy/dx和d^2y/dx^2 dy/dx,y=(1+x+x^2)e^x x^2+y^2=e^y求dy/dx 微分方程d^2y/dx^2+y=e^x的通解 微分方程.d^2y/dx^2=-yd^2y/dx^2=y 的解是C1 e^x + C2 e^(-x) 那么.d^2y/dx^2=-y 的解是什么呢. 微分方程 dy/dx=(e^y+3x)/x^2 dy/dx=(e^x+x)(1+y^2)通解 x=sin(y/x)+e^2 求dy/dx y=e^x/x^2+sin2x 求dy/dx dy/ dx +2y=x*e^x的通解, [e^(x+y)-e^x]dx+[e^(x+y)-e^y]dy=0求通解 y是x 的隐函数的导数,1）、xy-e^x+e^y=1,求y' .2)设y=sin(x+y),求dy/dx,d^2y/dx^2; d^2y/dx^2=e^2y,当x=0时y=0,(dy/dx)|x=0=0；求解微分方程的初值问题 高数题设x=(t+1)e^t,y=t^2*e^t,求d^2y/dx^2 求微分的题目一道,x=e^(-t)sint,y=e^tcost,求 d^2y/dx^2