1.在三角形ABC中,设tanA:tanB=(2c-b):b,求A的值.2.在三角形ABC中,设acosA+bcosB=ccosC,求三角形ABC的形状.
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![1.在三角形ABC中,设tanA:tanB=(2c-b):b,求A的值.2.在三角形ABC中,设acosA+bcosB=ccosC,求三角形ABC的形状.](/uploads/image/z/7064335-55-5.jpg?t=1.%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%AE%BEtanA%EF%BC%9AtanB%3D%EF%BC%882c-b%EF%BC%89%EF%BC%9Ab%2C%E6%B1%82A%E7%9A%84%E5%80%BC.2.%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%AE%BEacosA%2BbcosB%3DccosC%2C%E6%B1%82%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E5%BD%A2%E7%8A%B6.)
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