初二下学期分式加减应用求解~已知:(1/m) - 1/(m+1) = 1/[m(m+1)] 请你化简:1/[(n+1)(n+2)] + 1/[n+2)(n+3)] +……+ 1/[(n+2006)(n+2007)] + 1/[(n+2007)(n+2008)]
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![初二下学期分式加减应用求解~已知:(1/m) - 1/(m+1) = 1/[m(m+1)] 请你化简:1/[(n+1)(n+2)] + 1/[n+2)(n+3)] +……+ 1/[(n+2006)(n+2007)] + 1/[(n+2007)(n+2008)]](/uploads/image/z/7096530-66-0.jpg?t=%E5%88%9D%E4%BA%8C%E4%B8%8B%E5%AD%A6%E6%9C%9F%E5%88%86%E5%BC%8F%E5%8A%A0%E5%87%8F%E5%BA%94%E7%94%A8%E6%B1%82%E8%A7%A3%7E%E5%B7%B2%E7%9F%A5%EF%BC%9A%281%2Fm%29+-+1%2F%28m%2B1%29+%3D+1%2F%5Bm%28m%2B1%29%5D+%E8%AF%B7%E4%BD%A0%E5%8C%96%E7%AE%80%EF%BC%9A1%2F%5B%28n%2B1%29%28n%2B2%29%5D++%2B++1%2F%5Bn%2B2%29%28n%2B3%29%5D+%2B%E2%80%A6%E2%80%A6%2B++1%2F%5B%28n%2B2006%29%28n%2B2007%29%5D++%2B++1%2F%5B%28n%2B2007%29%28n%2B2008%29%5D)
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初二下学期分式加减应用求解~已知:(1/m) - 1/(m+1) = 1/[m(m+1)] 请你化简:1/[(n+1)(n+2)] + 1/[n+2)(n+3)] +……+ 1/[(n+2006)(n+2007)] + 1/[(n+2007)(n+2008)]
初二下学期分式加减应用求解~
已知:(1/m) - 1/(m+1) = 1/[m(m+1)] 请你化简:1/[(n+1)(n+2)] + 1/[n+2)(n+3)] +……
+ 1/[(n+2006)(n+2007)] + 1/[(n+2007)(n+2008)]
初二下学期分式加减应用求解~已知:(1/m) - 1/(m+1) = 1/[m(m+1)] 请你化简:1/[(n+1)(n+2)] + 1/[n+2)(n+3)] +……+ 1/[(n+2006)(n+2007)] + 1/[(n+2007)(n+2008)]
1/[(n+1)(n+2)] + 1/[n+2)(n+3)] +……+ 1/[(n+2006)(n+2007)] + 1/[(n+2007)(n+2008)]
=1/(n+1)-1/(n+2)+1/(n+2)-1/(n+3)+······+1/(n+2007)-1/(n+2008)
=1/(n+1)-1/(n+2008)
=2007/(n+1)(n+2008)
初二下学期分式加减应用求解~已知:(1/m) - 1/(m+1) = 1/[m(m+1)] 请你化简:1/[(n+1)(n+2)] + 1/[n+2)(n+3)] +……+ 1/[(n+2006)(n+2007)] + 1/[(n+2007)(n+2008)]
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