已知函数f(x)=x³+3ax²+(3-6a)x+12a-4 (a是实数). (1)证明:曲线y已知函数f(x)=x³+3ax²+(3-6a)x+12a-4 (a是实数). (1)证明:曲线y=f(x)在x=0处的切线过点(2,2).
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![已知函数f(x)=x³+3ax²+(3-6a)x+12a-4 (a是实数). (1)证明:曲线y已知函数f(x)=x³+3ax²+(3-6a)x+12a-4 (a是实数). (1)证明:曲线y=f(x)在x=0处的切线过点(2,2).](/uploads/image/z/7104169-1-9.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%EF%BC%9Dx%26%23179%3B%2B3ax%26%23178%3B%2B%EF%BC%883-6a%EF%BC%89x%2B12a-4+%EF%BC%88a%E6%98%AF%E5%AE%9E%E6%95%B0%EF%BC%89.+%EF%BC%881%EF%BC%89%E8%AF%81%E6%98%8E%EF%BC%9A%E6%9B%B2%E7%BA%BFy%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%EF%BC%9Dx%26%23179%3B%2B3ax%26%23178%3B%2B%EF%BC%883-6a%EF%BC%89x%2B12a-4++%EF%BC%88a%E6%98%AF%E5%AE%9E%E6%95%B0%EF%BC%89.+%EF%BC%881%EF%BC%89%E8%AF%81%E6%98%8E%EF%BC%9A%E6%9B%B2%E7%BA%BFy%EF%BC%9Df%EF%BC%88x%EF%BC%89%E5%9C%A8x%EF%BC%9D0%E5%A4%84%E7%9A%84%E5%88%87%E7%BA%BF%E8%BF%87%E7%82%B9%EF%BC%882%2C2%EF%BC%89.)
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已知函数f(x)=x³+3ax²+(3-6a)x+12a-4 (a是实数). (1)证明:曲线y已知函数f(x)=x³+3ax²+(3-6a)x+12a-4 (a是实数). (1)证明:曲线y=f(x)在x=0处的切线过点(2,2).
已知函数f(x)=x³+3ax²+(3-6a)x+12a-4 (a是实数). (1)证明:曲线y
已知函数f(x)=x³+3ax²+(3-6a)x+12a-4 (a是实数). (1)证明:曲线y=f(x)在x=0处的切线过点(2,2). (2)若f(x)在x=x.处取得极小值 x.属于(1,3),求a的取值范围.
已知函数f(x)=x³+3ax²+(3-6a)x+12a-4 (a是实数). (1)证明:曲线y已知函数f(x)=x³+3ax²+(3-6a)x+12a-4 (a是实数). (1)证明:曲线y=f(x)在x=0处的切线过点(2,2).
求导,f'(x)=3x^2+6ax+3-6a
X=0时,有f(0)=12a-4,f'(0)=3-6a
求切线方程可得,y=(3-6a)x+12a-4
x=2时,解得y=2,
即,曲线f(x)在x=0处的切线过点(2,2)
第二问有点复杂,你等等.