如图所示,△ABC中,AB=AC,CD平分∠ACB交AB于点D,AE平行DC交BC的延长线于点E,已知∠E=36°(1)求证:AC平分∠BAE(2)直接写出图中除△ABC外的所有等腰三角形
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![如图所示,△ABC中,AB=AC,CD平分∠ACB交AB于点D,AE平行DC交BC的延长线于点E,已知∠E=36°(1)求证:AC平分∠BAE(2)直接写出图中除△ABC外的所有等腰三角形](/uploads/image/z/7116878-38-8.jpg?t=%E5%A6%82%E5%9B%BE%E6%89%80%E7%A4%BA%2C%E2%96%B3ABC%E4%B8%AD%2CAB%3DAC%2CCD%E5%B9%B3%E5%88%86%E2%88%A0ACB%E4%BA%A4AB%E4%BA%8E%E7%82%B9D%2CAE%E5%B9%B3%E8%A1%8CDC%E4%BA%A4BC%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8E%E7%82%B9E%2C%E5%B7%B2%E7%9F%A5%E2%88%A0E%3D36%C2%B0%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9AAC%E5%B9%B3%E5%88%86%E2%88%A0BAE%EF%BC%882%EF%BC%89%E7%9B%B4%E6%8E%A5%E5%86%99%E5%87%BA%E5%9B%BE%E4%B8%AD%E9%99%A4%E2%96%B3ABC%E5%A4%96%E7%9A%84%E6%89%80%E6%9C%89%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2)
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