证明相似三角形如图,AB=AC,AD是三角形ABC的角平分线,E为AD上任意一点,BE的延长线交AC于点F,交过点C且平行于AB的直线于点P,EF=8,EP=18,求BE
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![证明相似三角形如图,AB=AC,AD是三角形ABC的角平分线,E为AD上任意一点,BE的延长线交AC于点F,交过点C且平行于AB的直线于点P,EF=8,EP=18,求BE](/uploads/image/z/7143912-0-2.jpg?t=%E8%AF%81%E6%98%8E%E7%9B%B8%E4%BC%BC%E4%B8%89%E8%A7%92%E5%BD%A2%E5%A6%82%E5%9B%BE%2CAB%3DAC%2CAD%E6%98%AF%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF%2CE%E4%B8%BAAD%E4%B8%8A%E4%BB%BB%E6%84%8F%E4%B8%80%E7%82%B9%2CBE%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%A4AC%E4%BA%8E%E7%82%B9F%2C%E4%BA%A4%E8%BF%87%E7%82%B9C%E4%B8%94%E5%B9%B3%E8%A1%8C%E4%BA%8EAB%E7%9A%84%E7%9B%B4%E7%BA%BF%E4%BA%8E%E7%82%B9P%2CEF%3D8%2CEP%3D18%2C%E6%B1%82BE)
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证明相似三角形如图,AB=AC,AD是三角形ABC的角平分线,E为AD上任意一点,BE的延长线交AC于点F,交过点C且平行于AB的直线于点P,EF=8,EP=18,求BE
证明相似三角形
如图,AB=AC,AD是三角形ABC的角平分线,E为AD上任意一点,BE的延长线交AC于点F,交过点C且平行于AB的直线于点P,EF=8,EP=18,求BE
证明相似三角形如图,AB=AC,AD是三角形ABC的角平分线,E为AD上任意一点,BE的延长线交AC于点F,交过点C且平行于AB的直线于点P,EF=8,EP=18,求BE
延长AE、PC交于O
AB=AC,AD⊥BC,CO=AB
AB:PO=BE:EP=BE:18
AB:PC=BF:FP=(BE+8):10
PO=PC+AB,BE:18=(BE+8):(BE+18)
BE=12.