数学大侠please help me已知点p(x,y)在圆x^2+y^2-6x-6y+14=0上求x^2+Y^2+2x+3的最大值和最小值.答案是51和11
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![数学大侠please help me已知点p(x,y)在圆x^2+y^2-6x-6y+14=0上求x^2+Y^2+2x+3的最大值和最小值.答案是51和11](/uploads/image/z/7148611-19-1.jpg?t=%E6%95%B0%E5%AD%A6%E5%A4%A7%E4%BE%A0please+help+me%E5%B7%B2%E7%9F%A5%E7%82%B9p%28x%2Cy%29%E5%9C%A8%E5%9C%86x%5E2%2By%5E2-6x-6y%2B14%3D0%E4%B8%8A%E6%B1%82x%5E2%2BY%5E2%2B2x%2B3%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E5%92%8C%E6%9C%80%E5%B0%8F%E5%80%BC.%E7%AD%94%E6%A1%88%E6%98%AF51%E5%92%8C11)
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数学大侠please help me已知点p(x,y)在圆x^2+y^2-6x-6y+14=0上求x^2+Y^2+2x+3的最大值和最小值.答案是51和11
数学大侠please help me
已知点p(x,y)在圆x^2+y^2-6x-6y+14=0上
求x^2+Y^2+2x+3的最大值和最小值.
答案是51和11
数学大侠please help me已知点p(x,y)在圆x^2+y^2-6x-6y+14=0上求x^2+Y^2+2x+3的最大值和最小值.答案是51和11
x^2+Y^2+2x+3=(x+1)^2+Y^2+2
也就是求圆上一点到(-1,0)的最短距离的平方和最长距离平方,结果再加上2,就是最小值和最大值了
将上式配方,移项,开方,再带入下式,使之只含有x或y。这样问题就简化了。
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数学大侠please help me已知点p(x,y)在圆x^2+y^2-6x-6y+14=0上求x^2+Y^2+2x+3的最大值和最小值.答案是51和11
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