Matlab中A(1,R(1:2))及A(1,R(2:-1:A =4 2 3 1 54 2 5 3 14 3 5 2 1R =2 1 5 3 4A(1,R(1:2))= A(1,R(2:-1:1))结果是:A =4 2 3 1 54 2 5 3 14 3 5 2 1具体的A(1,R(1:2)),A(1,R(2:-1:求指教?
来源:学生作业帮助网 编辑:作业帮 时间:2024/12/01 20:15:33
xRN@~ФBv-K ïD@_DE
oWpv[bA^fgoIRL֞
aagYz(;4&I0K( &B
?1T'I&Nk$qdX
~{ۣբ3!^eljONy[D(YKH{B"
Matlab中A(1,R(1:2))及A(1,R(2:-1:A =4 2 3 1 54 2 5 3 14 3 5 2 1R =2 1 5 3 4A(1,R(1:2))= A(1,R(2:-1:1))结果是:A =4 2 3 1 54 2 5 3 14 3 5 2 1具体的A(1,R(1:2)),A(1,R(2:-1:求指教?
Matlab中A(1,R(1:2))及A(1,R(2:-1:
A =
4 2 3 1 5
4 2 5 3 1
4 3 5 2 1
R =
2 1 5 3 4
A(1,R(1:2))= A(1,R(2:-1:1))
结果是:
A =
4 2 3 1 5
4 2 5 3 1
4 3 5 2 1
具体的A(1,R(1:2)),A(1,R(2:-1:求指教?
Matlab中A(1,R(1:2))及A(1,R(2:-1:A =4 2 3 1 54 2 5 3 14 3 5 2 1R =2 1 5 3 4A(1,R(1:2))= A(1,R(2:-1:1))结果是:A =4 2 3 1 54 2 5 3 14 3 5 2 1具体的A(1,R(1:2)),A(1,R(2:-1:求指教?
A(1,R(2:-1:1)) %2:-1:1意思是从2递减1,一直减到1结束,故列为R(2)和
%R(1),其所对应的是1和2,即整句为A(1,2)和A(1,1),赋给A(1,R(1:2))
A(1,R(1:2)) %将A(1,2)和A(1,1)的值赋给A(1,1)和A(1,2).
故总的意思是A(1,2)和A(1,1)的位置发生了变换.正确的结果应为
A =
2 4 3 1 5
4 2 5 3 1
4 3 5 2 1
matlab中a(1:
Matlab中A(1,R(1:2))及A(1,R(2:-1:A =4 2 3 1 54 2 5 3 14 3 5 2 1R =2 1 5 3 4A(1,R(1:2))= A(1,R(2:-1:1))结果是:A =4 2 3 1 54 2 5 3 14 3 5 2 1具体的A(1,R(1:2)),A(1,R(2:-1:求指教?
matlab中plot(1:size(A,2),
matlab中 a(1:2)=[
matlab中 A(:)=1:
matlab中A(2:3) %A(2:1:
Matlab中 double(a(:,:,1))是什么意思
matlab中t=[A;1]是什么意思
matlab中a(1:500,:知道了,
请问在matlab中 A(1:N,:
matlab中 if( (A(m,n-1)
MATLAB中已知A = [ 8 1 6; 3 5 7; 4 9 2 ]; 请教A([3 2],2:-1:1)为多少 及为什么 谢谢
matlab中a(i)=1/sqrt(2)是什么意思
matlab中A(i,2:
MATLAB中abs(a,求给出具体答案及用法!
matlab >> syms r x>> limit(-1/216*a*(36*r^3*exp(-6*r/a)+18*r^2*exp(-6*r/a)*a+6*r*exp(-6*r/a)*a^2+exp(-6*r/a)*a^3-a^3),r ,inf)ans =limit(-1/216*a*(36*r^3*exp(-6*r/a)+18*r^2*exp(-6*r/a)*a+6*r*exp(-6*r/a)*a^2+exp(-6*r/a)*a^3-a^3),r = inf)应该可以求
matlab x(a,1:
Matlab中A=zeros(2,4);A(:)=1:8则A为?