已知圆C:(x+2a)^2+(y-a)^2=9,直线l:(m+2)x+(1-m)y+m-4=0,(1)求圆C的圆心轨迹方程.(2)是否存在直线L,使得对符意的实数a,L都与圆C相切,若存在,求L的方程,若不存在说明理由.
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![已知圆C:(x+2a)^2+(y-a)^2=9,直线l:(m+2)x+(1-m)y+m-4=0,(1)求圆C的圆心轨迹方程.(2)是否存在直线L,使得对符意的实数a,L都与圆C相切,若存在,求L的方程,若不存在说明理由.](/uploads/image/z/7160181-69-1.jpg?t=%E5%B7%B2%E7%9F%A5%E5%9C%86C%3A%28x%2B2a%29%5E2%2B%28y-a%29%5E2%3D9%2C%E7%9B%B4%E7%BA%BFl%3A%28m%2B2%29x%2B%281-m%29y%2Bm-4%3D0%2C%281%29%E6%B1%82%E5%9C%86C%E7%9A%84%E5%9C%86%E5%BF%83%E8%BD%A8%E8%BF%B9%E6%96%B9%E7%A8%8B.%EF%BC%882%EF%BC%89%E6%98%AF%E5%90%A6%E5%AD%98%E5%9C%A8%E7%9B%B4%E7%BA%BFL%2C%E4%BD%BF%E5%BE%97%E5%AF%B9%E7%AC%A6%E6%84%8F%E7%9A%84%E5%AE%9E%E6%95%B0a%2CL%E9%83%BD%E4%B8%8E%E5%9C%86C%E7%9B%B8%E5%88%87%2C%E8%8B%A5%E5%AD%98%E5%9C%A8%2C%E6%B1%82L%E7%9A%84%E6%96%B9%E7%A8%8B%2C%E8%8B%A5%E4%B8%8D%E5%AD%98%E5%9C%A8%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1.)
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