Ia+2I+Ia-1I化简

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Ia+2I+Ia-1I化简
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Ia+2I+Ia-1I化简
Ia+2I+Ia-1I化简

Ia+2I+Ia-1I化简
若a+20
∴Ia+2I+Ia-1I=(a+2)+(a-1)=a+2+a-1=2a+1
若a+2≥0且a-1≤0
则-2≤a≤1
这时,Ia+2I+Ia-1I=(a+2)-(a-1)=a+2-a+1=3
因此,当a1时,Ia+2I+Ia-1I=2a+1

要讨论啊，分几种情况。
第一种：a>=1
原式=a+2+a-1=2a+1
第二种：2<=a<1
a+2+1-a=3
第三种：a<-2
-a-2+1-a=-2a-1

1.a>=1
原式=a+2+a-1=2a+1
2.-2<=a<1
a+2+1-a=3
3.a<-2
-a-2+1-a=-2a-1

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