还要有式子!
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/17 02:36:09
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还要有式子!
还要有式子!
还要有式子!
(1)原式=[x+(2y-3)]*[x-(2y-3)]=x^2-(2y-3)^2=x^2-4y^2+12y-9
(2)原式=2004^2-(2004+1)(2004-1)=2004^2-(2004^2-1)=1
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