设x,y满足约束条件2x-y+2≥0,8x-y-4≤0,y≥x,若目标函数z=abx+y(a>0,b>0)的最大值为8,则a+b的最小我画出来区域,点(1/2,0)在内,我把这个点带入 AB=16,而答案是把(1,4)点带入,AB=4,这样不是最大值啊
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![设x,y满足约束条件2x-y+2≥0,8x-y-4≤0,y≥x,若目标函数z=abx+y(a>0,b>0)的最大值为8,则a+b的最小我画出来区域,点(1/2,0)在内,我把这个点带入 AB=16,而答案是把(1,4)点带入,AB=4,这样不是最大值啊](/uploads/image/z/7181620-52-0.jpg?t=%E8%AE%BEx%2Cy%E6%BB%A1%E8%B6%B3%E7%BA%A6%E6%9D%9F%E6%9D%A1%E4%BB%B62x-y%2B2%E2%89%A50%2C8x-y-4%E2%89%A40%2Cy%E2%89%A5x%2C%E8%8B%A5%E7%9B%AE%E6%A0%87%E5%87%BD%E6%95%B0z%3Dabx%2By%EF%BC%88a%3E0%2Cb%3E0%EF%BC%89%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E4%B8%BA8%2C%E5%88%99a%2Bb%E7%9A%84%E6%9C%80%E5%B0%8F%E6%88%91%E7%94%BB%E5%87%BA%E6%9D%A5%E5%8C%BA%E5%9F%9F%2C%E7%82%B9%281%2F2%2C0%29%E5%9C%A8%E5%86%85%2C%E6%88%91%E6%8A%8A%E8%BF%99%E4%B8%AA%E7%82%B9%E5%B8%A6%E5%85%A5+AB%3D16%2C%E8%80%8C%E7%AD%94%E6%A1%88%E6%98%AF%E6%8A%8A%EF%BC%881%2C4%EF%BC%89%E7%82%B9%E5%B8%A6%E5%85%A5%2CAB%3D4%2C%E8%BF%99%E6%A0%B7%E4%B8%8D%E6%98%AF%E6%9C%80%E5%A4%A7%E5%80%BC%E5%95%8A)
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