如图,AC垂直BC于点C,BC=a,CA=b,AB=c,圆O与直线AB,BC.CA,都相切,求圆O的半径.我算是(b2+cb)/a+b+c,请说明理由我设半径为X,做OH垂直于AC于H并延长交AB于M,做ON垂直BA延长线于N,则AH=AN=b—x有三角形ABC相
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![如图,AC垂直BC于点C,BC=a,CA=b,AB=c,圆O与直线AB,BC.CA,都相切,求圆O的半径.我算是(b2+cb)/a+b+c,请说明理由我设半径为X,做OH垂直于AC于H并延长交AB于M,做ON垂直BA延长线于N,则AH=AN=b—x有三角形ABC相](/uploads/image/z/7223630-14-0.jpg?t=%E5%A6%82%E5%9B%BE%2CAC%E5%9E%82%E7%9B%B4BC%E4%BA%8E%E7%82%B9C%2CBC%3Da%2CCA%3Db%2CAB%3Dc%2C%E5%9C%86O%E4%B8%8E%E7%9B%B4%E7%BA%BFAB%2CBC.CA%2C%E9%83%BD%E7%9B%B8%E5%88%87%2C%E6%B1%82%E5%9C%86O%E7%9A%84%E5%8D%8A%E5%BE%84.%E6%88%91%E7%AE%97%E6%98%AF%28b2%2Bcb%29%2Fa%2Bb%2Bc%2C%E8%AF%B7%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1%E6%88%91%E8%AE%BE%E5%8D%8A%E5%BE%84%E4%B8%BAX%EF%BC%8C%E5%81%9AOH%E5%9E%82%E7%9B%B4%E4%BA%8EAC%E4%BA%8EH%E5%B9%B6%E5%BB%B6%E9%95%BF%E4%BA%A4AB%E4%BA%8EM%EF%BC%8C%E5%81%9AON%E5%9E%82%E7%9B%B4BA%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8EN%EF%BC%8C%E5%88%99AH%3DAN%3Db%E2%80%94x%E6%9C%89%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9B%B8)
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