设等差数列{an}的前n项和为Sn,且S4=20,S8=72,则S12=?
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设等差数列{an}的前n项和为Sn,且S4=20,S8=72,则S12=?
设等差数列{an}的前n项和为Sn,且S4=20,S8=72,则S12=?
设等差数列{an}的前n项和为Sn,且S4=20,S8=72,则S12=?
S4,S8-S4,S12-S8成等差数列
即:20,52,S12-72成等差数列
∴20+S12-72=52×2
S12=156
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