设函数f (x)有反函数g(x),f(a)=3,f'(a)=1,f''(a)=2,求g''(3)答案是-2,但是用反函数求导g''(x)=d(f'(x))/ f'(x)=f''(x) / f'(x),所以g''(3)=f''(a) / f'(a)=2 为什么和答案差了一个负号?请高手们看看错在了哪?
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![设函数f (x)有反函数g(x),f(a)=3,f'(a)=1,f''(a)=2,求g''(3)答案是-2,但是用反函数求导g''(x)=d(f'(x))/ f'(x)=f''(x) / f'(x),所以g''(3)=f''(a) / f'(a)=2 为什么和答案差了一个负号?请高手们看看错在了哪?](/uploads/image/z/7233968-56-8.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f+%28x%29%E6%9C%89%E5%8F%8D%E5%87%BD%E6%95%B0g%28x%29%2Cf%28a%29%3D3%2Cf%27%28a%29%3D1%2Cf%27%27%28a%29%3D2%2C%E6%B1%82g%27%27%283%29%E7%AD%94%E6%A1%88%E6%98%AF-2%2C%E4%BD%86%E6%98%AF%E7%94%A8%E5%8F%8D%E5%87%BD%E6%95%B0%E6%B1%82%E5%AF%BCg%27%27%28x%29%3Dd%EF%BC%88f%27%28x%29%EF%BC%89%2F+f%27%28x%29%3Df%27%27%28x%29+%2F+f%27%28x%29%2C%E6%89%80%E4%BB%A5g%27%27%283%29%3Df%27%27%28a%29+%2F+f%27%28a%29%3D2+%E4%B8%BA%E4%BB%80%E4%B9%88%E5%92%8C%E7%AD%94%E6%A1%88%E5%B7%AE%E4%BA%86%E4%B8%80%E4%B8%AA%E8%B4%9F%E5%8F%B7%3F%E8%AF%B7%E9%AB%98%E6%89%8B%E4%BB%AC%E7%9C%8B%E7%9C%8B%E9%94%99%E5%9C%A8%E4%BA%86%E5%93%AA%3F)
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