log a b=log b a,则:ab=?a不等于b
来源:学生作业帮助网 编辑:作业帮 时间:2024/12/01 03:12:00
x)OWHTHI
:O;f3+1>Ɏk;KI*ǣ,\Άbgs:XsA u
Q-KK%Š^d.4[2:^
ՏGЌ3҉@bvȮDg^4x0k!Vbp"H ? 4~OGb=P>@A SM
log a b=log b a,则:ab=?a不等于b
log a b=log b a,则:ab=?
a不等于b
log a b=log b a,则:ab=?a不等于b
应该有个a≠b吧,ab=1
log a b=lnb/lna
log b a=lna/lnb
因为log a b=log b a
所以lnb/lna=lna/lnb
(lnb)^2=(lna)^2
lnb=lna 或者lnb=-lna
因为a≠b
所以lna=-lnb
得到lna+lnb=0
ln(ab)=0
所以ab=1
log a b=log b a,则:ab=?a不等于b
已知 log (a) ab=1/p ,则 log (ab) a/b=__ __.
log(2)5=a,log(2)7=b用ab表示log(35)28
关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1
关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1
log a c+log b c=0(c≠1),则ab+c-abc=?
log a c+log b c=0(c≠1),则ab+c-abc=?
log(8)a+log(4)b^2=5,log(8)b+log(4)a^2=7,求log(2)ab的值
公式:log(a)(b)*log(b)(a)=?
设a>b>1,log(a)b+log(b)a=10/3,则log(a)b-log(b)a=
log(a)(b)=log(c)(b) /log(c)(a) 怎么证log(a)(b)=log(c)(b) /log(c)(a)怎么证
求证 log(a)^(b)=1/log(b)^(a)求证 log(a)^(b)=1/log(b)^(a)
a,b,x 都是正数,4[log(a)x]²+[3log(b)x]²=8log(a)x*log(b)x,则a,b的关系
27-1/ 若a>0,b>0,a*b>1,log(1/2)[a]=ln2,则log(a)[b]与log(1/2)[a]的关系是:()?(A)log(a)b< log(1/2)[a](B)log(a)b= log(1/2)[a](C)log(a)b>log(1/2)[a](D)log(a)b与log(1/2)[a] 无法比较大小我做到一半就做不下去了:a=(1/2)^(ln2)log
设log(18)(9)=a log(18)(5)=b ,用ab表示log(36)(45)设log(18)(9)=a log(18)(5)=b ,用ab表示log(36)(45)
已知log(14)7=a log(14)5=b 用ab表示log(35)70=log(3)4*log(4)8*log(8)m=log(4)2 求m
已知log(3)2=a log(5)2=b用ab表示log(30)90
log(a)(b)=log(b)(a)(a≠1,b≠1,c≠1),则ab=(log(x)(y))^2+(log(y)(x))^2=1,则y可用x表示为前面那个括号是底数