进进如图,在R他△ABC中,∠ACB=45°,∠BAC=90°,AB=AC,点D是AB的中点,AF⊥CD于H交BC于F,BE‖AC交AF的延长线于D,求证:BC垂直平分DE
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![进进如图,在R他△ABC中,∠ACB=45°,∠BAC=90°,AB=AC,点D是AB的中点,AF⊥CD于H交BC于F,BE‖AC交AF的延长线于D,求证:BC垂直平分DE](/uploads/image/z/7260083-35-3.jpg?t=%E8%BF%9B%E8%BF%9B%E5%A6%82%E5%9B%BE%2C%E5%9C%A8R%E4%BB%96%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0ACB%3D45%C2%B0%2C%E2%88%A0BAC%3D90%C2%B0%2CAB%3DAC%2C%E7%82%B9D%E6%98%AFAB%E7%9A%84%E4%B8%AD%E7%82%B9%2CAF%E2%8A%A5CD%E4%BA%8EH%E4%BA%A4BC%E4%BA%8EF%2CBE%E2%80%96AC%E4%BA%A4AF%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8ED%2C%E6%B1%82%E8%AF%81%EF%BC%9ABC%E5%9E%82%E7%9B%B4%E5%B9%B3%E5%88%86DE)
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