若1/1x2+1/2x3+.+1/nx(n+1)=98/99求n
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若1/1x2+1/2x3+.+1/nx(n+1)=98/99求n
若1/1x2+1/2x3+.+1/nx(n+1)=98/99求n
若1/1x2+1/2x3+.+1/nx(n+1)=98/99求n
1/nx(n+1)=1/n-1/(n+1)
1/1x2+1/2x3+.+1/n-1/(n+1)=98/99 可转化为
(1-1/2)+(1/2-1/3)+.+(1/n-1/(n+1))=98/99中间可消除一些然后整理得
1- 1/(n+1)=98/99
1/(n+1)=1/99
n=98
98
1X2+2X3+3X4+.NX(N+1)
1X2+2X3+3X4+.NX(N+1)规律
1X2+2X3.+nx(n+1)
若1/1x2+1/2x3+.+1/nx(n+1)=98/99求n
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1X2+2X3+3X4+...+nX(n+1)= 1X2+2X3+3X4+...+10X11= (写过程,如1/3 乘.)1X2+2X3+3X4+...+nX(n+1)= ? 1X2+2X3+3X4+...+10X11= ?(写过程,如1/3 乘.)
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1x2=1/3(1x2x3=0x1x2 ) 2x3=1/3(2x3x4-1x2x3) 3x4=1/3(3x4x5- 2x3x4) 1x2+2x3+3x4+...+nx(n+1)=
1X2=1/3(1X2X3-0X1X2) 2X3=1/3(2X3X4-1X2X3) 发现1X2+2X3+3X4+、、、、、、+nX(n+1)=?谁知道