limx趋向于兀sin(x-兀)/x-兀.用洛必达法则求极限
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limx趋向于兀sin(x-兀)/x-兀.用洛必达法则求极限
limx趋向于兀sin(x-兀)/x-兀.用洛必达法则求极限
limx趋向于兀sin(x-兀)/x-兀.用洛必达法则求极限
lim(x->π) sin(x-π)/(x-π ) (0/0)
=lim(x->π) cos(x-π)
=1
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