(x-y+1)^2-(x+y-3)^2

来源：学生作业帮助网 编辑：作业帮 时间：2024/07/17 07:50:48
(x-y+1)^2-(x+y-3)^2
x)ӨЭ6Ԍ3ըЮ5lِ$n цjD`*c! F&F#.P@ 10t!u jddL q[tgv>ݾi뚧{c=vEөa4Yӌ &@YC]dХHI|

(x-y+1)^2-(x+y-3)^2
(x-y+1)^2-(x+y-3)^2

(x-y+1)^2-(x+y-3)^2
(x-y+1)^2-(x+y-3)^2
=[(x-y+1)+(x+y-3)]*[(x-y+1)-(x+y-3)]
=(x-2)(4-2y)
=2(x-2)(2-y)

(x-y+1)^2-(x+y-3)^2
=（x-y+1+x+y-3)(x-y+1-x-y+3)
=(2x-2)((4-2y)
=4(x-1)(2-y)

平方差公式得到：（2-2Y）(2X-2)提取2得到4（1-Y）(X+1)

x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x² 若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值 x(x-y)2-(y-x)3 (3x-y)^2+(3x+y)(3x-y),x=1,y=-2 二元一次方程 ：2(x+y)-(x-y)=3 (x+y)-2(x-y)=1 (x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5) 2(x+y)-3(x-y)=1 6(x+y)+(x-y)=51 {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 变量x,y满足约束条件,x+y>=3,x-y>=-1,2x-y (Y-X)^3*(X-Y)^m+(X-Y) ^m+1*(Y-X)^2 (x-y)^2+(x+y)(x-y) 其中 X =3 Y=-1 [2/3x-2/x+y(x+y/3x-x-y)]/x-y/x 化简：{2/3x-2/(x+y)[(x+y)/3x-x-y]}/(x+y)/x 计算2/3x-2/x+y(x+y/3x-x-y)/x-y/x 化简3x-2/(x+y)[(x+y)/3x-x-y]÷(x-y)/x [(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y 1、(-7x^y)(2x^y-3xy^3+xy) 2、((x-y)^6)/((y-x)^3)/(x-y) x+y+2(-x-y+1)=3(1-y-x)-4-(y+x-1),x+y=?