当1/x-1/y=2时,求分式2x+3xy-2y/x-2xy-y的值如题

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当1/x-1/y=2时,求分式2x+3xy-2y/x-2xy-y的值如题
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当1/x-1/y=2时,求分式2x+3xy-2y/x-2xy-y的值如题
当1/x-1/y=2时,求分式2x+3xy-2y/x-2xy-y的值
如题

当1/x-1/y=2时,求分式2x+3xy-2y/x-2xy-y的值如题
1/x-1/y=2时
(y-x)/xy=2
y-x=2xy
2x+3xy-2y/x-2xy-y
=[3xy-2(y-x)]/[-2xy-(y-x)]
=-xy/-4xy
=1/4

求分式2x+3xy-2y/x-2xy-y的值
是不是求:(2x+3xy-2y)/(x-2xy-y)的值
若是,那么,原式=(2/y-2/x+3)/(1/y-1/x-2) (分子和分母同时除以xy)
=(-4+3)/(-2-2)
=1/4