计算:(a+2)(a-2)-(2a-1)²+(a+1)²;(x-6)(x²+x+1)-x(2x+1)(3x-1).
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/27 06:52:29
![计算:(a+2)(a-2)-(2a-1)²+(a+1)²;(x-6)(x²+x+1)-x(2x+1)(3x-1).](/uploads/image/z/759501-45-1.jpg?t=%E8%AE%A1%E7%AE%97%EF%BC%9A%EF%BC%88a%2B2%EF%BC%89%EF%BC%88a-2%EF%BC%89-%EF%BC%882a-1%EF%BC%89%26%23178%3B%2B%EF%BC%88a%2B1%EF%BC%89%26%23178%3B%EF%BC%9B%EF%BC%88x-6%EF%BC%89%EF%BC%88x%26%23178%3B%2Bx%2B1%EF%BC%89-x%282x%2B1%29%283x-1%29.)
x
0AB"S5D.a T%#H -+E=!g/6u]
݂ 0P\.v#3zXRfF,
P+}<
+F|3b` LlvJ%h"APMO"CHPY 5&! <55%Ԅo -
计算:(a+2)(a-2)-(2a-1)²+(a+1)²;(x-6)(x²+x+1)-x(2x+1)(3x-1).
计算:(a+2)(a-2)-(2a-1)²+(a+1)²;(x-6)(x²+x+1)-x(2x+1)(3x-1).
计算:(a+2)(a-2)-(2a-1)²+(a+1)²;(x-6)(x²+x+1)-x(2x+1)(3x-1).
(a+2)(a-2)-(2a-1)²+(a+1)²
=a²-4-(4a²-4a+1)+(a²+2a+1)
=a²-4-4a²+4a-1+a²+2a+1
=-2a²+6a-4
(x-6)(x²+x+1)-x(2x+1)(3x-1)
=x³+x²+x-6x²-6x-6-x(6x²+x-1)
=x³-5x²-5x-6-6x³-x²+x
=-5x³-6x²-4x-6
计算(a²-2a)/a 分式计算
计算(a^2+a+1)/(a+1)-(a^2-3a+1)/(a-3)
计算:-a³(a²-a-1)+a(-a³+2a).
计算:(2a+3)(a²+a-1)
计算:-2a(a²b+a-1)
计算:a²(a-1)-2a(1/2a²-1/2a+1).
计算1-(a-1)/a÷[a/(a+2)-1/(a2+2a)]等于?
计算:( -2a)²÷ a
计算[(a+b)^2-(a+b)]*(a+b)
计算【2a/(2a-1)-1/(4a平方-2a)】/【1+(4a平方+1)/4a】计算【2a/(2a-1)-1/(4a平方-2a)】/【1+(4a平方+1)/4a】
计算:(a+3a+5a+...+2013a)-(2a+4a+6a+...+2012a)=?
计算(a+3a+5a+.+2003a)-(2a+4a+6a+.+2004a)
计算[a-2/(a^2+2a)-2a-1/(a^2-4)]÷a^2+a-2/a^2+4a+4
计算:(1)(a/a^2-1)+(3a+1/a^2-1)+(2a+3/1-a^2)
计算(a+2)(a平方-2a+4)-(a-1)(a平方+a+1)
计算:1-[a- 1/(1-a)]²÷[(a²-a+1)/(a²-2a+1)]
计算:a^2+a-1/a+1-a^2-3a+1/a-3(要过程)
初二数学题:计算下列各式:[(a+1)(a-2)/(a的平方-4a+4)-a/a的平方-2a]÷a/a-2