设三元非齐次线性方程组AX=b中,距阵A的秩为2,且u1=(1,2,2)T,u2=(3,2,1)T是方程组的两个解,则此方程组的通解为( )n-r=3-2=1 所以Ax=0的基础解系中只有一个向量,u2-u1=(2,0,-1)T是Ax=0的非零解,是Ax
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![设三元非齐次线性方程组AX=b中,距阵A的秩为2,且u1=(1,2,2)T,u2=(3,2,1)T是方程组的两个解,则此方程组的通解为( )n-r=3-2=1 所以Ax=0的基础解系中只有一个向量,u2-u1=(2,0,-1)T是Ax=0的非零解,是Ax](/uploads/image/z/7609684-4-4.jpg?t=%E8%AE%BE%E4%B8%89%E5%85%83%E9%9D%9E%E9%BD%90%E6%AC%A1%E7%BA%BF%E6%80%A7%E6%96%B9%E7%A8%8B%E7%BB%84AX%3Db%E4%B8%AD%2C%E8%B7%9D%E9%98%B5A%E7%9A%84%E7%A7%A9%E4%B8%BA2%2C%E4%B8%94u1%3D%281%2C2%2C2%29T%2Cu2%3D%283%2C2%2C1%29T%E6%98%AF%E6%96%B9%E7%A8%8B%E7%BB%84%E7%9A%84%E4%B8%A4%E4%B8%AA%E8%A7%A3%2C%E5%88%99%E6%AD%A4%E6%96%B9%E7%A8%8B%E7%BB%84%E7%9A%84%E9%80%9A%E8%A7%A3%E4%B8%BA%EF%BC%88+%EF%BC%89n-r%3D3-2%3D1+%E6%89%80%E4%BB%A5Ax%EF%BC%9D0%E7%9A%84%E5%9F%BA%E7%A1%80%E8%A7%A3%E7%B3%BB%E4%B8%AD%E5%8F%AA%E6%9C%89%E4%B8%80%E4%B8%AA%E5%90%91%E9%87%8F%2Cu2%EF%BC%8Du1%EF%BC%9D%282%2C0%2C-1%29T%E6%98%AFAx%EF%BC%9D0%E7%9A%84%E9%9D%9E%E9%9B%B6%E8%A7%A3%2C%E6%98%AFAx)
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