大学物理题,受力分析.一根绳子挂着质量为M的小球,小球在水平面内做匀速圆周运动,绳子与铅垂方向的夹角为a,求绳子对小球拉力T.有两种做法,1:T乘以cos a减Mg=0.2:T-Mg乘以cos a=0问哪个正确,说明
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![大学物理题,受力分析.一根绳子挂着质量为M的小球,小球在水平面内做匀速圆周运动,绳子与铅垂方向的夹角为a,求绳子对小球拉力T.有两种做法,1:T乘以cos a减Mg=0.2:T-Mg乘以cos a=0问哪个正确,说明](/uploads/image/z/7629156-36-6.jpg?t=%E5%A4%A7%E5%AD%A6%E7%89%A9%E7%90%86%E9%A2%98%2C%E5%8F%97%E5%8A%9B%E5%88%86%E6%9E%90.%E4%B8%80%E6%A0%B9%E7%BB%B3%E5%AD%90%E6%8C%82%E7%9D%80%E8%B4%A8%E9%87%8F%E4%B8%BAM%E7%9A%84%E5%B0%8F%E7%90%83%2C%E5%B0%8F%E7%90%83%E5%9C%A8%E6%B0%B4%E5%B9%B3%E9%9D%A2%E5%86%85%E5%81%9A%E5%8C%80%E9%80%9F%E5%9C%86%E5%91%A8%E8%BF%90%E5%8A%A8%2C%E7%BB%B3%E5%AD%90%E4%B8%8E%E9%93%85%E5%9E%82%E6%96%B9%E5%90%91%E7%9A%84%E5%A4%B9%E8%A7%92%E4%B8%BAa%2C%E6%B1%82%E7%BB%B3%E5%AD%90%E5%AF%B9%E5%B0%8F%E7%90%83%E6%8B%89%E5%8A%9BT.%E6%9C%89%E4%B8%A4%E7%A7%8D%E5%81%9A%E6%B3%95%2C1%3AT%E4%B9%98%E4%BB%A5cos+a%E5%87%8FMg%3D0.2%3AT-Mg%E4%B9%98%E4%BB%A5cos+a%3D0%E9%97%AE%E5%93%AA%E4%B8%AA%E6%AD%A3%E7%A1%AE%2C%E8%AF%B4%E6%98%8E)
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