1.y=sin(1/2x+π/3),x属于【-2π,2π】的单调减区间2.y=2tan(2x+π/4),x属于【-2π,2π】的单调增区间
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![1.y=sin(1/2x+π/3),x属于【-2π,2π】的单调减区间2.y=2tan(2x+π/4),x属于【-2π,2π】的单调增区间](/uploads/image/z/7637495-23-5.jpg?t=1.y%3Dsin%281%2F2x%2B%CF%80%2F3%EF%BC%89%2Cx%E5%B1%9E%E4%BA%8E%E3%80%90-2%CF%80%2C2%CF%80%E3%80%91%E7%9A%84%E5%8D%95%E8%B0%83%E5%87%8F%E5%8C%BA%E9%97%B42.y%3D2tan%EF%BC%882x%2B%CF%80%2F4%EF%BC%89%2Cx%E5%B1%9E%E4%BA%8E%E3%80%90-2%CF%80%2C2%CF%80%E3%80%91%E7%9A%84%E5%8D%95%E8%B0%83%E5%A2%9E%E5%8C%BA%E9%97%B4)
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1.y=sin(1/2x+π/3),x属于【-2π,2π】的单调减区间2.y=2tan(2x+π/4),x属于【-2π,2π】的单调增区间
1.y=sin(1/2x+π/3),x属于【-2π,2π】的单调减区间
2.y=2tan(2x+π/4),x属于【-2π,2π】的单调增区间
1.y=sin(1/2x+π/3),x属于【-2π,2π】的单调减区间2.y=2tan(2x+π/4),x属于【-2π,2π】的单调增区间
1,-π/6≤1/2x+π/3≤4π/3
那么很明显:画出y=sint(t=1/2x+π/3)图像易得
递减区间为:t∈[π,4π/3]U那么t=1/2x+π/3就可以得到x的取值范围了x∈[π/3,2π]
2,同理,-15π/4≤2x+π/4≤17π/4
画出图进行确定即可,还有就是根据y=tant(t=2x+π/4)单调区间[-π/2+kπ,π/2+kπ]