已知函数f1(x)=e^|x-2a+1|,f2(x)=e^(|x-a|+1),x∈R,1≤a≤6(1)若a=2,求使f1(x)=f2(x)的x的值;(2)若|f1(x)-f2(x)|=f2(x)-f1(x)对于任意的实数x∈R恒成立,求a的取值范围;(3)求函数g(x)=[f1(x)+f2(x) ]/2 -
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![已知函数f1(x)=e^|x-2a+1|,f2(x)=e^(|x-a|+1),x∈R,1≤a≤6(1)若a=2,求使f1(x)=f2(x)的x的值;(2)若|f1(x)-f2(x)|=f2(x)-f1(x)对于任意的实数x∈R恒成立,求a的取值范围;(3)求函数g(x)=[f1(x)+f2(x) ]/2 -](/uploads/image/z/7640387-35-7.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f1%EF%BC%88x%EF%BC%89%3De%5E%7Cx-2a%2B1%7C%2Cf2%EF%BC%88x%EF%BC%89%3De%5E%28%7Cx-a%7C%2B1%29%2Cx%E2%88%88R%2C1%E2%89%A4a%E2%89%A46%EF%BC%881%EF%BC%89%E8%8B%A5a%3D2%2C%E6%B1%82%E4%BD%BFf1%28x%29%3Df2%28x%29%E7%9A%84x%E7%9A%84%E5%80%BC%EF%BC%9B%EF%BC%882%EF%BC%89%E8%8B%A5%7Cf1%28x%29-f2%28x%29%7C%3Df2%28x%29-f1%28x%29%E5%AF%B9%E4%BA%8E%E4%BB%BB%E6%84%8F%E7%9A%84%E5%AE%9E%E6%95%B0x%E2%88%88R%E6%81%92%E6%88%90%E7%AB%8B%2C%E6%B1%82a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%EF%BC%9B%EF%BC%883%EF%BC%89%E6%B1%82%E5%87%BD%E6%95%B0g%EF%BC%88x%EF%BC%89%3D%5Bf1%28x%29%2Bf2%28x%29+%5D%2F2+-)
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