1/[1+(t^3)+(t^2)+t]•6/t =(6/t)-3/(1+t)-[(3t+3)/(1+t^2)]这是用什么方法分解到第二部的,这是用的待定系数法吗
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![1/[1+(t^3)+(t^2)+t]•6/t =(6/t)-3/(1+t)-[(3t+3)/(1+t^2)]这是用什么方法分解到第二部的,这是用的待定系数法吗](/uploads/image/z/7654119-15-9.jpg?t=1%2F%5B1%2B%28t%5E3%29%2B%28t%5E2%29%2Bt%5D%26%238226%3B6%2Ft+%3D%286%2Ft%29-3%2F%281%2Bt%29-%5B%283t%2B3%29%2F%281%2Bt%5E2%29%5D%E8%BF%99%E6%98%AF%E7%94%A8%E4%BB%80%E4%B9%88%E6%96%B9%E6%B3%95%E5%88%86%E8%A7%A3%E5%88%B0%E7%AC%AC%E4%BA%8C%E9%83%A8%E7%9A%84%2C%E8%BF%99%E6%98%AF%E7%94%A8%E7%9A%84%E5%BE%85%E5%AE%9A%E7%B3%BB%E6%95%B0%E6%B3%95%E5%90%97)
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