(4x-7)(5x+7)=0 )
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(4x-7)(5x+7)=0 )
(4x-7)(5x+7)=0 )
(4x-7)(5x+7)=0 )
已经分解完了
4x-7=0,5x+7=0
x=7/4,x=-7/5
4x-7=0或5x+7=0
x1=7/4 x2=-7/5
20(x-7/4)(x+5/7)=0
这个还有什么过程啊 ··没有了··已经分解好了···两个数成绩为0,所以其中有1个为0或者两个都是0,由此得出4X-7=0或者5X+7=0,得出X1=7/4,X2=-7/5
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(4x-7)(5x+7)=0 )
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