空间直角坐标系关于直线对称求点问题,若点M与N(2,5,0)关于直线l对称,求点M的坐标l方程为 x-y-4z+12=0 2x+y-2z+3=0如果计算麻烦的话可以告诉一下思路么
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![空间直角坐标系关于直线对称求点问题,若点M与N(2,5,0)关于直线l对称,求点M的坐标l方程为 x-y-4z+12=0 2x+y-2z+3=0如果计算麻烦的话可以告诉一下思路么](/uploads/image/z/7797356-44-6.jpg?t=%E7%A9%BA%E9%97%B4%E7%9B%B4%E8%A7%92%E5%9D%90%E6%A0%87%E7%B3%BB%E5%85%B3%E4%BA%8E%E7%9B%B4%E7%BA%BF%E5%AF%B9%E7%A7%B0%E6%B1%82%E7%82%B9%E9%97%AE%E9%A2%98%2C%E8%8B%A5%E7%82%B9M%E4%B8%8EN%282%2C5%2C0%29%E5%85%B3%E4%BA%8E%E7%9B%B4%E7%BA%BFl%E5%AF%B9%E7%A7%B0%2C%E6%B1%82%E7%82%B9M%E7%9A%84%E5%9D%90%E6%A0%87l%E6%96%B9%E7%A8%8B%E4%B8%BA+x-y-4z%2B12%3D0+2x%2By-2z%2B3%3D0%E5%A6%82%E6%9E%9C%E8%AE%A1%E7%AE%97%E9%BA%BB%E7%83%A6%E7%9A%84%E8%AF%9D%E5%8F%AF%E4%BB%A5%E5%91%8A%E8%AF%89%E4%B8%80%E4%B8%8B%E6%80%9D%E8%B7%AF%E4%B9%88)
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