2x+4※(36-x)=100
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![2x+4※(36-x)=100](/uploads/image/z/7802264-56-4.jpg?t=2x%2B4%E2%80%BB%2836-x%29%3D100)
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2x+4※(36-x)=100
2x+4※(36-x)=100
2x+4※(36-x)=100
x-2x+3x-4x+5x.+99x-100x=25求解
2x+3x+4x+5x+x+6x+7x=100
2x+4※(36-x)=100
解方程:2x+4x+6x...+100x=1-(x+3x+5x+...+99x)
1x+2x+3x+4x+5x+6x+7x…+99x=100
解方程:x-2x+3x-4x+...+99x-100x=25
解方程:x-2x+3x-4x+.+99x-100x=25
x-2x+3x-4x+...+99x-100x=25
[(x+6)/(x-6)][(x-4)/(x+4)]^2+[(x-6)/(x+6)][(x+9)/(x-9)]^2=2(x^2+36)/(x^2-36)
先化简再求值(x+3x+5x+7x+.+101x)-(2x+4x+6x+...100x),其中x=51分之2
已知x^4+x^3+x^3+x^2+x^1+1=0,求x^100+x^99+x^98+x^97+x^96的值
(X+X)+(X-X)+(X*X)+(X/X)=100
解方程 式子 6-2x+3x=3x-4x+3x+18 6-x+3x=2x-5x+1 2x-1=5x-36-2x+3x=3x-4x+3x+18 6-x+3x=2x-5x+12x-1=5x-3
f(x)=x(x-1)(x+2)(x-3)(x+4)……(x+100),求f'(1)
一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少?
当x=2,求1/x*(x+2)+1/(x+2)*(x++4)+1/(x+4)*(x+6)+.+1/(x+98)*(x+100)的值
当x=2,求1/x(x+2)+1/(x+2)*(x++4)+1/(x+4)*(x+6)+.+1/(x+98)*(x+100)的值