在边长为2a的正三角形ABC的两边AB,AC上有两点D,E,线段DE平分正三角形ABC的面积.设AD=x,DE=y,则用x表示y的函数关系式为?定义域为?答案是y=根号下[(x-2a^2/x)^2+2a^2] x∈[a,2a],
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![在边长为2a的正三角形ABC的两边AB,AC上有两点D,E,线段DE平分正三角形ABC的面积.设AD=x,DE=y,则用x表示y的函数关系式为?定义域为?答案是y=根号下[(x-2a^2/x)^2+2a^2] x∈[a,2a],](/uploads/image/z/7955889-33-9.jpg?t=%E5%9C%A8%E8%BE%B9%E9%95%BF%E4%B8%BA2a%E7%9A%84%E6%AD%A3%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E4%B8%A4%E8%BE%B9AB%2CAC%E4%B8%8A%E6%9C%89%E4%B8%A4%E7%82%B9D%2CE%2C%E7%BA%BF%E6%AE%B5DE%E5%B9%B3%E5%88%86%E6%AD%A3%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E9%9D%A2%E7%A7%AF.%E8%AE%BEAD%3Dx%2CDE%3Dy%2C%E5%88%99%E7%94%A8x%E8%A1%A8%E7%A4%BAy%E7%9A%84%E5%87%BD%E6%95%B0%E5%85%B3%E7%B3%BB%E5%BC%8F%E4%B8%BA%3F%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BA%3F%E7%AD%94%E6%A1%88%E6%98%AFy%3D%E6%A0%B9%E5%8F%B7%E4%B8%8B%5B%28x-2a%5E2%2Fx%29%5E2%2B2a%5E2%5D+x%E2%88%88%5Ba%2C2a%5D%2C)
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