已知定义在R上的函数f(x)=1/3ax^3+1/2bx^2+cx(a<b<c)在x=1时取得极值,且y=f(x)的图象有一点处的切线斜率为-a(1)求证:0≤b/a<1(2)若f(x)在区间(s,t)上为增函数,求证:-2
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![已知定义在R上的函数f(x)=1/3ax^3+1/2bx^2+cx(a<b<c)在x=1时取得极值,且y=f(x)的图象有一点处的切线斜率为-a(1)求证:0≤b/a<1(2)若f(x)在区间(s,t)上为增函数,求证:-2](/uploads/image/z/800264-56-4.jpg?t=%E5%B7%B2%E7%9F%A5%E5%AE%9A%E4%B9%89%E5%9C%A8R%E4%B8%8A%E7%9A%84%E5%87%BD%E6%95%B0f%28x%29%3D1%2F3ax%5E3%2B1%2F2bx%5E2%2Bcx%EF%BC%88a%EF%BC%9Cb%EF%BC%9Cc%EF%BC%89%E5%9C%A8x%3D1%E6%97%B6%E5%8F%96%E5%BE%97%E6%9E%81%E5%80%BC%2C%E4%B8%94y%3Df%EF%BC%88x%EF%BC%89%E7%9A%84%E5%9B%BE%E8%B1%A1%E6%9C%89%E4%B8%80%E7%82%B9%E5%A4%84%E7%9A%84%E5%88%87%E7%BA%BF%E6%96%9C%E7%8E%87%E4%B8%BA-a%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9A0%E2%89%A4b%2Fa%EF%BC%9C1%EF%BC%882%EF%BC%89%E8%8B%A5f%EF%BC%88x%EF%BC%89%E5%9C%A8%E5%8C%BA%E9%97%B4%EF%BC%88s%2Ct%EF%BC%89%E4%B8%8A%E4%B8%BA%E5%A2%9E%E5%87%BD%E6%95%B0%2C%E6%B1%82%E8%AF%81%3A-2)
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