如图,在△ABD和△ACE中,AB=AD,AC=AE,∠BAD=∠CAE,连接BC,DE相交于点F,BC与AD相交于点G.已知BC=DE,∠ABC=∠CBD,试说明FD²=FG*FB
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![如图,在△ABD和△ACE中,AB=AD,AC=AE,∠BAD=∠CAE,连接BC,DE相交于点F,BC与AD相交于点G.已知BC=DE,∠ABC=∠CBD,试说明FD²=FG*FB](/uploads/image/z/812776-40-6.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABD%E5%92%8C%E2%96%B3ACE%E4%B8%AD%2CAB%3DAD%2CAC%3DAE%2C%E2%88%A0BAD%3D%E2%88%A0CAE%2C%E8%BF%9E%E6%8E%A5BC%2CDE%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9F%2CBC%E4%B8%8EAD%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9G.%E5%B7%B2%E7%9F%A5BC%3DDE%2C%E2%88%A0ABC%3D%E2%88%A0CBD%2C%E8%AF%95%E8%AF%B4%E6%98%8EFD%26%23178%3B%3DFG%2AFB)
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