如图,已知△ABC中,AB=AC,∠BAC=90°,直角EPF的顶点P是BC的中点,两边PE、PF分别交AB、AC于点E、F,给出以下四个结论:①AE=CF;②△EPF是等腰三角形;③S四边形AEPF=二分之一S△ABC;④EF=AP.当∠EPF在△AB
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/12 04:43:55
![如图,已知△ABC中,AB=AC,∠BAC=90°,直角EPF的顶点P是BC的中点,两边PE、PF分别交AB、AC于点E、F,给出以下四个结论:①AE=CF;②△EPF是等腰三角形;③S四边形AEPF=二分之一S△ABC;④EF=AP.当∠EPF在△AB](/uploads/image/z/812843-35-3.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%B7%B2%E7%9F%A5%E2%96%B3ABC%E4%B8%AD%2CAB%3DAC%2C%E2%88%A0BAC%3D90%C2%B0%2C%E7%9B%B4%E8%A7%92EPF%E7%9A%84%E9%A1%B6%E7%82%B9P%E6%98%AFBC%E7%9A%84%E4%B8%AD%E7%82%B9%2C%E4%B8%A4%E8%BE%B9PE%E3%80%81PF%E5%88%86%E5%88%AB%E4%BA%A4AB%E3%80%81AC%E4%BA%8E%E7%82%B9E%E3%80%81F%2C%E7%BB%99%E5%87%BA%E4%BB%A5%E4%B8%8B%E5%9B%9B%E4%B8%AA%E7%BB%93%E8%AE%BA%EF%BC%9A%E2%91%A0AE%3DCF%EF%BC%9B%E2%91%A1%E2%96%B3EPF%E6%98%AF%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2%EF%BC%9B%E2%91%A2S%E5%9B%9B%E8%BE%B9%E5%BD%A2AEPF%3D%E4%BA%8C%E5%88%86%E4%B9%8B%E4%B8%80S%E2%96%B3ABC%EF%BC%9B%E2%91%A3EF%3DAP.%E5%BD%93%E2%88%A0EPF%E5%9C%A8%E2%96%B3AB)
xV_oV*(Rc`.|5>dc(lkJI{h͠.i-I6k?[i}_0֗t>ο=^JWɳۤ&H^i_Ҳ:`N#YJrU{ι}iD0 1h7m]Ub%K #,Ԡ}LuժfjΨ_F$^@@c֜ժA
bf %YuUɰJ\SEP ɓWo?erjwƵ<;z&MjݷZM'?^
*ѹ