(let ((x 2) (y 5)) (let* ((x 6)(z (+ x y)))(* z x) (display z)(newline);)(display x)(newline)(display y))
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/07 02:57:47
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(let ((x 2) (y 5)) (let* ((x 6)(z (+ x y)))(* z x) (display z)(newline);)(display x)(newline)(display y))
(let ((x 2) (y 5))
(let* ((x 6)(z (+ x y)))
(* z x)
(display z)
(newline);
)
(display x)
(newline)
(display y)
)
(let ((x 2) (y 5)) (let* ((x 6)(z (+ x y)))(* z x) (display z)(newline);)(display x)(newline)(display y))
ls还汇编呢.scheme就是一种专门的语言,运算符号是在变量前面的,比如(* z x) 就是z * x,display是显示,newline是另起一行,let是定义,这样说了应该能看懂了吧.
(let ((x 2) (y 5)) (let* ((x 6)(z (+ x y)))(* z x) (display z)(newline);)(display x)(newline)(display y))
1.given the function f(x) = 2x*2 +5x -7,find the values of:a) f(-2) b) f(4) c) f(x*2) d) (f(x))*2 e) f(x*2) -xf(x)2.let f(x) =1/2 (2*x (符号是二的x次方) +2*-x (二的-x次方))show that for any real values of x and y,f(x+y) +f (x-y) = 2f(x)f(y
5x(x-y)+2y(x-y)
化简:5(x-y)+2(x+y)-3(x-y)
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
(X+2Y)(5X-2Y)
(x+2y)(5x-2y)
4x+2y-5x-y
(2x-3y)-(5x-y)
(2X-3y)-(5x-y)
(x-y)^2+5(x-y)-14
(2x-5y)(3x+y)
因式分解(x-2y)(x-3y)+(x-4y)(x-5y)+(x-3y)(x-5y)+(x-2y)(x-4y)
(2x+y)²+(x+3y)(x-3y)-x(5x+8y)因式分解
[2(x-y)^5-8(x-y)^2(x+y)+6y(x-y)^2]÷2(x-y)^2[2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2]÷2(x-y)^2
[(x+2y)(x-2y)-(2x-y)^2+(3x-y))2x-5y)]/(-x)我急用
[(x+2y)(x-2y)-(2x-y)²+(3x-y(2x-5y)]/(-x)的解答
[(x+2y)^2-(x-y)(x+2y)-5y^2]÷(2y)