若x+y=3,xy=1,则x²+y²= x²+y²=﹙x+y﹚²+p=﹙x-y﹚²+q,则p=__,q=__
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/09 04:36:53
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若x+y=3,xy=1,则x²+y²= x²+y²=﹙x+y﹚²+p=﹙x-y﹚²+q,则p=__,q=__
若x+y=3,xy=1,则x²+y²= x²+y²=﹙x+y﹚²+p=﹙x-y﹚²+q,则p=__,q=__
若x+y=3,xy=1,则x²+y²= x²+y²=﹙x+y﹚²+p=﹙x-y﹚²+q,则p=__,q=__
p=x^2+y^2-(x+y)^2=-2xy=-2
q=x^2+y^2-(x-y)^2=2xy=2 对啦
p=x^2+y^2-(x+y)^2=-2xy=-2
q=x^2+y^2-(x-y)^2=2xy=2
p=-2 q=2