已知一抛物线与x轴的交点是A(-1,0)、B(m,0),且经过第四象限的点C(1,n),而m+n=-1,mn=-12,求疵抛物线的解析式.已知直线y=x/2+3与两个坐标轴交与A,B两点.把二次函数y=-x^2/4的图像线先左右,后上
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![已知一抛物线与x轴的交点是A(-1,0)、B(m,0),且经过第四象限的点C(1,n),而m+n=-1,mn=-12,求疵抛物线的解析式.已知直线y=x/2+3与两个坐标轴交与A,B两点.把二次函数y=-x^2/4的图像线先左右,后上](/uploads/image/z/8325374-14-4.jpg?t=%E5%B7%B2%E7%9F%A5%E4%B8%80%E6%8A%9B%E7%89%A9%E7%BA%BF%E4%B8%8Ex%E8%BD%B4%E7%9A%84%E4%BA%A4%E7%82%B9%E6%98%AFA%EF%BC%88-1%2C0%EF%BC%89%E3%80%81B%EF%BC%88m%2C0%EF%BC%89%2C%E4%B8%94%E7%BB%8F%E8%BF%87%E7%AC%AC%E5%9B%9B%E8%B1%A1%E9%99%90%E7%9A%84%E7%82%B9C%EF%BC%881%2Cn%EF%BC%89%2C%E8%80%8Cm%2Bn%3D-1%2Cmn%3D-12%2C%E6%B1%82%E7%96%B5%E6%8A%9B%E7%89%A9%E7%BA%BF%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F.%E5%B7%B2%E7%9F%A5%E7%9B%B4%E7%BA%BFy%3Dx%2F2%2B3%E4%B8%8E%E4%B8%A4%E4%B8%AA%E5%9D%90%E6%A0%87%E8%BD%B4%E4%BA%A4%E4%B8%8EA%2CB%E4%B8%A4%E7%82%B9.%E6%8A%8A%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0y%3D-x%5E2%2F4%E7%9A%84%E5%9B%BE%E5%83%8F%E7%BA%BF%E5%85%88%E5%B7%A6%E5%8F%B3%2C%E5%90%8E%E4%B8%8A)
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