1.求函数y=x^2-2ax+1(-1≤x≤1)的最值2.已知抛物线y=x^2-(m+1)x+m-1,设抛物线与x轴两个交点间的距离为d,求d的最小值
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![1.求函数y=x^2-2ax+1(-1≤x≤1)的最值2.已知抛物线y=x^2-(m+1)x+m-1,设抛物线与x轴两个交点间的距离为d,求d的最小值](/uploads/image/z/8326856-56-6.jpg?t=1.%E6%B1%82%E5%87%BD%E6%95%B0y%3Dx%5E2-2ax%2B1%28-1%E2%89%A4x%E2%89%A41%29%E7%9A%84%E6%9C%80%E5%80%BC2.%E5%B7%B2%E7%9F%A5%E6%8A%9B%E7%89%A9%E7%BA%BFy%3Dx%5E2-%28m%2B1%29x%2Bm-1%2C%E8%AE%BE%E6%8A%9B%E7%89%A9%E7%BA%BF%E4%B8%8Ex%E8%BD%B4%E4%B8%A4%E4%B8%AA%E4%BA%A4%E7%82%B9%E9%97%B4%E7%9A%84%E8%B7%9D%E7%A6%BB%E4%B8%BAd%2C%E6%B1%82d%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC)
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