高一数学必修待定系数法 这个题 f(x+1)=a(x+1)²+b(x+1)+c =a(x²+2x+1)+bx+b+c =ax²+2ax+a+bx+b+c 怎么出来的ax²+(2a+b)x+c
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![高一数学必修待定系数法 这个题 f(x+1)=a(x+1)²+b(x+1)+c =a(x²+2x+1)+bx+b+c =ax²+2ax+a+bx+b+c 怎么出来的ax²+(2a+b)x+c](/uploads/image/z/8330379-51-9.jpg?t=%E9%AB%98%E4%B8%80%E6%95%B0%E5%AD%A6%E5%BF%85%E4%BF%AE%E5%BE%85%E5%AE%9A%E7%B3%BB%E6%95%B0%E6%B3%95+%E8%BF%99%E4%B8%AA%E9%A2%98+f%EF%BC%88x%2B1%EF%BC%89%3Da%EF%BC%88x%2B1%EF%BC%89%26%23178%3B%EF%BC%8Bb%EF%BC%88x%2B1%EF%BC%89%2Bc++++++++++++++%3Da%EF%BC%88x%26%23178%3B%2B2x%EF%BC%8B1%EF%BC%89%2Bbx%2Bb%2Bc++++++++++++++%3Dax%26%23178%3B%2B2ax%2Ba%2Bbx%2Bb%2Bc+%E6%80%8E%E4%B9%88%E5%87%BA%E6%9D%A5%E7%9A%84ax%26%23178%3B%2B%EF%BC%882a%2Bb%EF%BC%89x%2Bc)
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