某小轿车的功率是66kw,其内燃机的效率是30%,则每小时消耗多少汽油?(q汽油=4.6×10^7J/kg)若按照以下解法:q×m×30%=P×t ==> m≈17.21kg;请问你是如何想的?若有不同意见,请说明一下……同样一
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![某小轿车的功率是66kw,其内燃机的效率是30%,则每小时消耗多少汽油?(q汽油=4.6×10^7J/kg)若按照以下解法:q×m×30%=P×t ==> m≈17.21kg;请问你是如何想的?若有不同意见,请说明一下……同样一](/uploads/image/z/839371-67-1.jpg?t=%E6%9F%90%E5%B0%8F%E8%BD%BF%E8%BD%A6%E7%9A%84%E5%8A%9F%E7%8E%87%E6%98%AF66kw%2C%E5%85%B6%E5%86%85%E7%87%83%E6%9C%BA%E7%9A%84%E6%95%88%E7%8E%87%E6%98%AF30%25%2C%E5%88%99%E6%AF%8F%E5%B0%8F%E6%97%B6%E6%B6%88%E8%80%97%E5%A4%9A%E5%B0%91%E6%B1%BD%E6%B2%B9%3F%EF%BC%88q%E6%B1%BD%E6%B2%B9%3D4.6%C3%9710%5E7J%2Fkg%EF%BC%89%E8%8B%A5%E6%8C%89%E7%85%A7%E4%BB%A5%E4%B8%8B%E8%A7%A3%E6%B3%95%EF%BC%9Aq%C3%97m%C3%9730%EF%BC%85%3DP%C3%97t+%3D%3D%3E+m%E2%89%8817.21kg%EF%BC%9B%E8%AF%B7%E9%97%AE%E4%BD%A0%E6%98%AF%E5%A6%82%E4%BD%95%E6%83%B3%E7%9A%84%3F%E8%8B%A5%E6%9C%89%E4%B8%8D%E5%90%8C%E6%84%8F%E8%A7%81%2C%E8%AF%B7%E8%AF%B4%E6%98%8E%E4%B8%80%E4%B8%8B%E2%80%A6%E2%80%A6%E5%90%8C%E6%A0%B7%E4%B8%80)
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