矩形ABCD中,已知AB=2AD,E为AB的中点,M为DE的中点,将△AED沿DE折起,使AB=AC,求证:AM垂直平面BCDE.
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![矩形ABCD中,已知AB=2AD,E为AB的中点,M为DE的中点,将△AED沿DE折起,使AB=AC,求证:AM垂直平面BCDE.](/uploads/image/z/8408070-54-0.jpg?t=%E7%9F%A9%E5%BD%A2ABCD%E4%B8%AD%2C%E5%B7%B2%E7%9F%A5AB%3D2AD%2CE%E4%B8%BAAB%E7%9A%84%E4%B8%AD%E7%82%B9%2CM%E4%B8%BADE%E7%9A%84%E4%B8%AD%E7%82%B9%2C%E5%B0%86%E2%96%B3AED%E6%B2%BFDE%E6%8A%98%E8%B5%B7%2C%E4%BD%BFAB%3DAC%2C%E6%B1%82%E8%AF%81%3AAM%E5%9E%82%E7%9B%B4%E5%B9%B3%E9%9D%A2BCDE.)
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