已知关于x的方程x²+2(a−1)x+a²−7a−4=0的两根为x1,x2,且满足x1x2−3x1−3x2−2=0.求[1+4/(a²−4)]×[(a+2)/a]注:“x”是字母“×”是乘号
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![已知关于x的方程x²+2(a−1)x+a²−7a−4=0的两根为x1,x2,且满足x1x2−3x1−3x2−2=0.求[1+4/(a²−4)]×[(a+2)/a]注:“x”是字母“×”是乘号](/uploads/image/z/8409463-7-3.jpg?t=%E5%B7%B2%E7%9F%A5%E5%85%B3%E4%BA%8Ex%E7%9A%84%E6%96%B9%E7%A8%8Bx%26%23178%3B%2B2%28a%26%238722%3B1%29x%2Ba%26%23178%3B%26%238722%3B7a%26%238722%3B4%3D0%E7%9A%84%E4%B8%A4%E6%A0%B9%E4%B8%BAx1%2Cx2%2C%E4%B8%94%E6%BB%A1%E8%B6%B3x1x2%26%238722%3B3x1%26%238722%3B3x2%26%238722%3B2%3D0.%E6%B1%82%5B1%2B4%2F%28a%26%23178%3B%26%238722%3B4%29%5D%C3%97%5B%28a%2B2%29%2Fa%5D%E6%B3%A8%3A%E2%80%9Cx%E2%80%9D%E6%98%AF%E5%AD%97%E6%AF%8D%E2%80%9C%C3%97%E2%80%9D%E6%98%AF%E4%B9%98%E5%8F%B7)
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