已知,AB=AC,求证:BD/CE=DF/EF
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已知,AB=AC,求证:BD/CE=DF/EF
已知,AB=AC,求证:BD/CE=DF/EF
已知,AB=AC,求证:BD/CE=DF/EF
过E点做辅助线EP//BD,交BC延长线与点P.角B=角P,角ACB=角ECP.因为角B=角ACB(就是条件中的角C),所以角ECP=角P.所以EC=EP.因为EP//BD,所以DF/EF=BD/EP,因此,DF/EF=BD/CE.