已知,梯形ABCD中,AB=CD,AD平行BC,对角线AC,BD相交于点O,AC垂直BD,DH垂直BC于H ,EF为中位线求证:EF=DH
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![已知,梯形ABCD中,AB=CD,AD平行BC,对角线AC,BD相交于点O,AC垂直BD,DH垂直BC于H ,EF为中位线求证:EF=DH](/uploads/image/z/8549317-37-7.jpg?t=%E5%B7%B2%E7%9F%A5%2C%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2CAB%EF%BC%9DCD%2CAD%E5%B9%B3%E8%A1%8CBC%2C%E5%AF%B9%E8%A7%92%E7%BA%BFAC%2CBD%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9O%2CAC%E5%9E%82%E7%9B%B4BD%2CDH%E5%9E%82%E7%9B%B4BC%E4%BA%8EH+%2CEF%E4%B8%BA%E4%B8%AD%E4%BD%8D%E7%BA%BF%E6%B1%82%E8%AF%81%EF%BC%9AEF%EF%BC%9DDH)
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