1-b分之1+1+b分之1+1+b²+1+b四次方(逐步通分)y²+3y+2分之1+y²+5y+6分之1+y²+7y+12分之1(裂项相消)
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/20 13:57:51
![1-b分之1+1+b分之1+1+b²+1+b四次方(逐步通分)y²+3y+2分之1+y²+5y+6分之1+y²+7y+12分之1(裂项相消)](/uploads/image/z/8572341-21-1.jpg?t=1-b%E5%88%86%E4%B9%8B1%2B1%2Bb%E5%88%86%E4%B9%8B1%2B1%2Bb%26%23178%3B%2B1%2Bb%E5%9B%9B%E6%AC%A1%E6%96%B9%EF%BC%88%E9%80%90%E6%AD%A5%E9%80%9A%E5%88%86%EF%BC%89y%26%23178%3B%2B3y%2B2%E5%88%86%E4%B9%8B1%2By%26%23178%3B%2B5y%2B6%E5%88%86%E4%B9%8B1%2By%26%23178%3B%2B7y%2B12%E5%88%86%E4%B9%8B1%EF%BC%88%E8%A3%82%E9%A1%B9%E7%9B%B8%E6%B6%88%EF%BC%89)
1-b分之1+1+b分之1+1+b²+1+b四次方(逐步通分)y²+3y+2分之1+y²+5y+6分之1+y²+7y+12分之1(裂项相消)
1-b分之1+1+b分之1+1+b²+1+b四次方(逐步通分)
y²+3y+2分之1+y²+5y+6分之1+y²+7y+12分之1(裂项相消)
1-b分之1+1+b分之1+1+b²+1+b四次方(逐步通分)y²+3y+2分之1+y²+5y+6分之1+y²+7y+12分之1(裂项相消)
1-b分之1+1+b分之1+1+b²分之1+1+b四次方分之1
=1/(1-b)+1/(1+b)+2/(1+b²)+4/(1+b⁴)
=(1+b+1-b)/(1-b²)+2/(1+b²)+4/(1+b²)
=(2+2b²+2-2b²)/(1-b⁴)+4/(1+b⁴)
=(4+4b⁴+4-4b⁴)/(1+b^8)
=8/(1+b^8)
(y²+3y+2)分之1+(y²+5y+6)分之1+(y²+7y+12)分之1
=1/(y+1)(y+2)+1/(y+2)(y+3)+1/(y+3)(y+4)
=1/(y+1)-1/(y+2)+1/(y+2)-1/(y+3)+1/(y+3)-1/(y+4)
=1/(y+1)-1/(y+4)
=(y+4-y-1)/(y+1)(y+4)
=3/(y²+5y+4)
1-b分之1+1+b分之1+1+b²+1+b四次方
=1-1/b+1+1/b+1+b²+1+b^4
=4+b²+b^4
y²+3y+2分之1+y²+5y+6分之1+y²+7y+12分之1
=y²+3y+1/2+y²+5y+1/6+y²+7y+1/12
=y²+y²+y²+3y+5y+7y+1/2+1/6+1/12
=3y²+15y+9/12
=3y²+15y+3/4