xy=9,x-y=-3则x²+3xy+y²=
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xy=9,x-y=-3则x²+3xy+y²=
xy=9,x-y=-3则x²+3xy+y²=
xy=9,x-y=-3则x²+3xy+y²=
x^2+3xy+y^2=(x-y)^2+5xy=(-3)^2+5*9=54
不懂发消息问我.
x-y=-3
(x-y)^2=x^2-2xy+y^2=9
又xy=9,所以x^2+y^2=27
所x^2-3xy+y^2=27-3×9=0,
若x²+xy-2y²=0,则x²+3xy+y²/x²+y²
x²+xy-2y²=0则x²+3xy+y²/x²+y²
xy=9,x-y=-3则x²+3xy+y²=
x²+xy-2y²=0,则x²+3xy+y²/x²+y²=?如题目.详细计算过程
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