作业帮A=1/2^10 + 1/(2^11 -1)+.+1/(2^11 -1),则A与1的大小关系为?
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A=1/2^10 + 1/(2^11 -1)+.+1/(2^11 -1),则A与1的大小关系为?
A=1/2^10 + 1/(2^11 -1)+.+1/(2^11 -1),则A与1的大小关系为?
A=1/2^10 + 1/(2^11 -1)+.+1/(2^11 -1),则A与1的大小关系为?
式子一共有 2^10 项,
A=1/2^10 + 1/(2^11 -1)+.+1/(2^11 -1)
< 1/2^10 + 1/2^10+.+1/2^10 = 1
就有A < 1
逻辑运算中A表示什么 (1) 0 · A = 0 (10) 1' = 0; 0' = 1 (2) 1 · A = A (11) 1 + A = 1 (3) A · A = A (12) 0 + A = A (4) A · A' = 0 (13) A + A = A (5) A · B = B · A (14) A + A' = 1 (6) A·(B·C) = (A·B)·C (15) A
【1】a+a=a×a a= [ ]【2】a×a=a÷a a=[ ]【3】a×a=a－a a=[ ] [4]a－a=a＋a a=[ ]
a+a+1+a+2+a+3+a+4+a+5+a+6+a+7.+a+2013+a+2014=?
逻辑运算中的A表示什么 (1) 0 · A = 0 (10) 1' = 0; 0' = 1 (2) 1 · A = A (11) 1 + A = 1 (3) A · A = A (12) 0 + A = A (4) A · A' = 0 (13) A + A = A (5) A · B = B · A (14) A + A' = 1 (6) A·(B·C) = (A·B)·C (15
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