#define S(x) 4*x*x+1 main() { int i=6,j=8; printf("%d\n",S(i+j)); }

#define s(x) 3 #define S(x) 3 #define S(x) 4*(x)*x+1 s(4)怎么计算 #define SETBIT(x,y) (x|=(1 define fun(x, #define configASSERT( x ) #define min(x,y) (x #define MIN(x,y)(x) #define __T(x) L ## x #define get2byte(x) ((x)[0] #define S(x) 4*x*x+1 main() { int i=6,j=8; printf(%d ,S(i+j)); } #define S(x) 4*x*x+1 main() { int i=6,j=8; printf(%d ,S(i+j)); } #define S(x)4 *(x)*x+1 main() {int k=5,j=2;printf(%d ,S(k+j));} 若有宏定义# define s(x) x*x-x,设int k=3; 问cout 求此程序的解释,就是#define s(x) 4*(x)*x+1这语句是什么意思啊,怎么运算#include#define s(x) 4*(x)*x+1main(){int k=5, j=2;printf(%d ,s(k+j));} #define SWP_TYPE(x) (((x).val >> 1) & 0x3f) #define set_bit(x,b) (x) |= (1U )define f(x)(x*x) 和 define f(x) x*x 之间的差别.