证明在定义在[a,正无穷)的连续函数符合罗尔定理,即罗尔定理的推广函数f(x)在(a,正无穷)可导,且lim(x→+a)f(x)=A,lim(x→正无穷)=A,证明存在ζ∈(a,正无穷),使得f '(ζ)=0.(顺便问一下:f(x)在
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![证明在定义在[a,正无穷)的连续函数符合罗尔定理,即罗尔定理的推广函数f(x)在(a,正无穷)可导,且lim(x→+a)f(x)=A,lim(x→正无穷)=A,证明存在ζ∈(a,正无穷),使得f '(ζ)=0.(顺便问一下:f(x)在](/uploads/image/z/8688264-24-4.jpg?t=%E8%AF%81%E6%98%8E%E5%9C%A8%E5%AE%9A%E4%B9%89%E5%9C%A8%5Ba%2C%E6%AD%A3%E6%97%A0%E7%A9%B7%EF%BC%89%E7%9A%84%E8%BF%9E%E7%BB%AD%E5%87%BD%E6%95%B0%E7%AC%A6%E5%90%88%E7%BD%97%E5%B0%94%E5%AE%9A%E7%90%86%2C%E5%8D%B3%E7%BD%97%E5%B0%94%E5%AE%9A%E7%90%86%E7%9A%84%E6%8E%A8%E5%B9%BF%E5%87%BD%E6%95%B0f%28x%29%E5%9C%A8%EF%BC%88a%2C%E6%AD%A3%E6%97%A0%E7%A9%B7%EF%BC%89%E5%8F%AF%E5%AF%BC%2C%E4%B8%94lim%28x%E2%86%92%2Ba%29f%28x%29%3DA%2Clim%28x%E2%86%92%E6%AD%A3%E6%97%A0%E7%A9%B7%EF%BC%89%3DA%2C%E8%AF%81%E6%98%8E%E5%AD%98%E5%9C%A8%CE%B6%E2%88%88%EF%BC%88a%2C%E6%AD%A3%E6%97%A0%E7%A9%B7%EF%BC%89%2C%E4%BD%BF%E5%BE%97f+%27%28%CE%B6%29%3D0.%EF%BC%88%E9%A1%BA%E4%BE%BF%E9%97%AE%E4%B8%80%E4%B8%8B%3Af%28x%29%E5%9C%A8)
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