已知点P是等边三角形ABC内一点,角APB,角BPC,角CPA的比是5:6:7,求以AP,BP,CP为边的三角形内角的比
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![已知点P是等边三角形ABC内一点,角APB,角BPC,角CPA的比是5:6:7,求以AP,BP,CP为边的三角形内角的比](/uploads/image/z/8697401-17-1.jpg?t=%E5%B7%B2%E7%9F%A5%E7%82%B9P%E6%98%AF%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E5%86%85%E4%B8%80%E7%82%B9%2C%E8%A7%92APB%2C%E8%A7%92BPC%2C%E8%A7%92CPA%E7%9A%84%E6%AF%94%E6%98%AF5%3A6%3A7%2C%E6%B1%82%E4%BB%A5AP%2CBP%2CCP%E4%B8%BA%E8%BE%B9%E7%9A%84%E4%B8%89%E8%A7%92%E5%BD%A2%E5%86%85%E8%A7%92%E7%9A%84%E6%AF%94)
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